Calendar Practice Set – Success Khan reasoning-ps-15-1 questions with answers and explanation.
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What will be the day of the week on 1st January, 2010 ? — 1 जनवरी 2010 को सप्ताह का दिन क्या होगा?
Answer: Option C Explanation: 2000 years have 2 odd days. Year 2001 2002 2003 2004 2005 2006 2007 2008 2009 Odd days 1 1 1 2 1 1 1 2 1 = 11 odd days = 4 odd days. 1st January, 2010 has 1 odd day. Total number of odd days = (2 + 4 + 1) = 7 = 0. ? 1st January, 2010 will be Sunday 2000 वर्ष में 2 विषम दिन हैं। वर्ष 2001 2002 2003 2004 2005 2006 2007 2008 विषम दिन 1 1 1 2 2 1 1 2 2 1 = 11 विषम दिन = 4 विषम दिन। 1 जनवरी, 2010 में 1 विषम दिन है। विषम की कुल संख्या दिन = (2 + 4 + 1) = 7 = 0 ? 1 जनवरी, 2010 रविवार होगा
Answer: Option D Explanation:09/12/2001—— Sunday No. of days between 9/12/71 & 9/12/2001 we know every year has 1 odd days we know leap year has 2 odd days Here, No. of normal years = 22 And no. of leap years = 8 So odd days = 22 + 16 = 38 i.e. 3 odd days (remainder when 38 is divided by 7, i.e. 3) Hence it was a Thursday. 09/12/2001- रविवार 9/12/71 और 9/12/2001 के बीच दिनों की संख्या हम जानते हैं कि हर साल 1 विषम दिन होते हैं हम जानते हैं कि लीप वर्ष में 2 विषम दिन होते हैं यहाँ, सामान्य वर्षों की संख्या = 22 और लीप वर्षों की संख्या = 8 इतने विषम दिन = 22 + 16 = 38 यानी 3 दिन (शेष जब 9, से विभाजित किया जाता है, अर्थात 3) इसलिए गुरुवार का दिन था
Answer: Option C Explanation:Count the number of days from 2005 onwards to get 0 odd day. Year 2005 2006 2007 2008 2010 2011 Odd days 1 1 1 2 1 1 = 7 or 0 odd day. ? Calendar for the year 2005 is the same as that for the year 2012. 0 विषम दिन प्राप्त करने के लिए 2005 से दिनों की संख्या गिनें। वर्ष 2005 2006 2007 2008 2010 अजीब दिन 1 1 1 2 2 1 = 7 या 0 विषम दिन। वर्ष 2005 का कैलेंडर वर्ष 2012 के समान है।
Answer: Option A Explanation:16th July, 1776 mean (1775 years + 6 months + 16 days) Now, 1600 years have 0 odd days. 100 years have 5 odd days 75 years contain 18 leap years and 57 ordinary years and therefore (36 + 57) or 93 or 2 odd days. ? 1775 years given 0 + 5 + 2 = 7 and so 0 odd days. Also number of days from 1st Jan. 1776 to 16th July,1776 Jan. Feb. March April May June July 31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days = 28 weeks + 2 days = 2 odd days ? Total number of odd days = 0 + 2 = 2. Hence the day on 16th July, 1776 was ‘Tuesday’. 16 जुलाई, 1776 माध्य (1775 वर्ष + 6 महीने + 16 दिन) अब, 1600 वर्षों में 0 विषम दिन हैं। 100 साल के 5 विषम दिन होते हैं 75 वर्ष में 18 लीप वर्ष और 57 साधारण वर्ष होते हैं और इसलिए (36 + 57) या 93 या 2 विषम दिन होते हैं। 1775 वर्ष दिए गए 0 + 5 + 2 = 7 और इसलिए 0 विषम दिन। 1 जनवरी 1776 से 16 जुलाई, 1776 तक के दिनों की संख्या भी जनवरी, मार्च अप्रैल मई जून जून जुलाई 31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 दिन = 28 सप्ताह + 2 दिन = 2 विषम दिन = विषम दिनों की कुल संख्या = 0 + 2 = 2 इसलिए 16 जुलाई, 1776 को दिन ‘मंगलवार’ था।
On January 12, 1980, it was Saturday. The day of the week on January 12, 1979 was – — 12 जनवरी, 1980 को शनिवार था। 12 जनवरी, 1979 को सप्ताह का दिन था –
Answer: Option B Explanation:The year 1979 being an ordinary year, it has 1 odd day. So, the day on 12th January 1980 is one day beyond on the day on 12th January, 1979. But, January 12, 1980 being Saturday. ? January 12, 1979 was Friday. वर्ष 1979 एक सामान्य वर्ष है, इसमें 1 विषम दिन है। तो, 12 जनवरी 1980 को दिन 12 जनवरी, 1979 से एक दिन आगे है। लेकिन, 12 जनवरी, 1980 शनिवार है। ? 12 जनवरी, 1979 को शुक्रवार था।
Answer: Option C Explanation:We go on counting the odd days from 1991 onwards till the sum is divisible by 7. The number of such days are 14 upto the year 2001. So, the calendar for 1991 will be repeated in the year 2002. हम 1991 के बाद से विषम दिनों की गणना करते हैं। जब तक कि राशि 7 से विभाज्य नहीं हो जाती है। वर्ष 2001 तक ऐसे दिनों की संख्या 14 है। इसलिए, 1991 के कैलेंडर को वर्ष 2002 में दोहराया जाएगा।
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